0=15y^2+26y+8

Solution for 0=15y^2+26y+8 equation:

0=15y^2+26y+8

We move all terms to the left:

0-(15y^2+26y+8)=0

We add all the numbers together, and all the variables

-(15y^2+26y+8)=0

We get rid of parentheses

-15y^2-26y-8=0

a = -15; b = -26; c = -8;
Δ = b2-4ac
Δ = -262-4·(-15)·(-8)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-14}{2*-15}=\frac{12}{-30}
=-2/5
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+14}{2*-15}=\frac{40}{-30}
=-1+1/3
$